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Challenges

Challenge 7.1

# Check if a year is a leap year

Challenge Level: Growing experience

## Requirement:

Write a program that takes a year as the input and displays a message saying if the year is a leap year or not.

Following is the algorithm to check if a year is a leap year or not:

1. if (year is not divisible by 4) then (it is a common year)
2. else if (year is not divisible by 100) then (it is a leap year)
3. else if (year is not divisible by 400) then (it is a common year)
4. else (it is a leap year)
Programming Reminders
# Print a string directly
print("Hello World!")

# Print a variable
print(my_var)

#### Variables

# Set a variable as a string
fruit_name = "Apple"

# Set a variable as an integer
pieces_of_fruit = 7

# Set a variable from a calculation
cost_of_fruit = pieces_of_fruit * cost_per_item

# Add one to a value
pieces_of_fruit += 1

#### Conditionals

# Find out the discount on fruit
if pieces_of_fruit > 100:
print("Bulk discount applies")
elif pieces_of_fruit > 5:
print("Discount applies")
else:
print("No discount")

#### For loops

# Print numbers 0-9 - remember Python starts counting from 0
for num in range(10):
print(num)

#### While loops

# Print numbers 0-9 using a while loop and a variable
num = 0
while num < 10:
print(num)

# Increment the variable by one.
# It will prevent an infinite loop!
num += 1 

#### Lists

# Create a list of fruit
fruit = ["Apple", "Banana", "Orange", "Pear"]

#### Functions

# Create a function which prints a greeting
def greeting(name):
print("Hello " + name)

# Call the function
greeting("Spiderman")

Enter your code in the editor below

Your results will be displayed here

Input Expected output Received output Status
1600
1600 is a leap year!

Not yet run ?
2000
2000 is a leap year!

Not yet run ?
2400
2400 is a leap year!

Not yet run ?
1700
1700 is not a leap year!

Not yet run ?
2100
2100 is not a leap year!

Not yet run ?
2300
2300 is not a leap year!

Not yet run ?